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Check if Array is Consecutive Integers
Objective: Given a array of unsorted numbers, check if all the numbers in the array are consecutive numbers.
Examples:
int [] arrA = {21,24,22,26,23,25};  True (All the integers are consecutive from 21 to 26) int [] arrB = {11,10,12,14,13};  True (All the integers are consecutive from 10 to 14) int [] arrC = {11,10,14,13};  False (Integers are not consecutive, 12 is missing)
Approach:
Naive Approach: Sorting . Time Complexity  O(nlogn).
Better Approach: Time Complexity  O(n).
 Find the Maximum and minimum elements in array (Say the array is arrA)
 Check if array length = maxmin+1
 Subtract the min from every element of the array.
 Check if array doesn't have duplicates
for Step 4
a) If array contains negative elements
 Create an aux array and put 0 at every position
 Navigate the main array and update the aux array as aux[arrA[i]]=1
 During step 2 if u find any index position already filled with 1, we have duplicates, return false
 This operation performs in O(n) time and O(n) space
b) If array does not contains negative elements  Time Complexity : O(n), Space Complexity : O(1)
 Navigate the array.
 Update the array as for ith index : arrA[arrA[i]] = arrA[arrA[i]]*1 (if it already not negative).
 If is already negative, we have duplicates, return false.
Code:
Output:
true true false
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