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91. Check if Array is Consecutive Integers

Objective: Given an array of unsorted numbers, check if all the numbers are consecutive.


int [] arrA = {21,24,22,26,23,25}; - True
(All the integers are consecutive from 21 to 26)
int [] arrB = {11,10,12,14,13}; - True
(All the integers are consecutive from 10 to 14)
int [] arrC = {11,10,14,13}; - False
(Integers are not consecutive, 12 is missing)


Naive Approach: Sorting. Time Complexity - O(nlogn).

Better Approach: Time Complexity - O(n).

  1. Find the Maximum and minimum elements in an array (Say the array is arrA)
  2. Check if array length   = max-min+1
  3. Subtract the min from every element of the array.
  4. Check if the array doesn't have duplicates

for Step 4

a) If the array contains negative elements

  1. Create an aux array and put 0 at every position
  2. Navigate the main array and update the aux array as aux[arrA[i]]=1
  3. During step 2 if u find any index position already filled with 1, we have duplicates, return false
  4. This operation performs in O(n) time and O(n) space

b) If the array does not contain negative elements - Time Complexity: O(n), Space Complexity: O(1)

  1. Navigate the array.
  2. Update the array as for ith index:- arrA[arrA[i]] = arrA[arrA[i]]*-1 (if it is already not negative).
  3. If is already negative, we have duplicates, return false.