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553. Minimize Scheduling Headaches: Clone Yourself for Overlapping Events
Problem Statement
You have a calendar with n events, each defined by a start time and a finish time. Some events may overlap, making it impossible for a single person to attend all of them. To ensure that every event is attended, you need to create k clones of yourself. Each clone can attend a subset of nonoverlapping events. The objective is to minimize the number of clones required to cover all events.
Example 1:
Events: [(1, 3),(2, 5),(4, 6)] Output: 2 Clone 1  (1, 3) and (4, 6). Clone 2  (2, 5)
Example 2:
Events: [(1,4),(2,3),(3,5),(7,9)] Output: 3 Clone 1  (1, 4) Clone 2  (2, 3) Clone 3  (3,5) and (7,9)
Approach: Greedy solution
 Sorting Events:
 This sorts the events based on their start times, ensuring we process them in chronological order.
 Min Heap Initialization:
 The min heap is used to keep track of the end times of clones, always allowing access to the clone that finishes the earliest.
 Processing Events:
 The forloop iterates over each event and determines if the earliest available clone (the one with the smallest end time) can attend the event.
 If the clone can attend, its end time is updated.
 If no clone can attend, a new clone is created and added to the queue.
 Counting Clones:
 TAfter processing all events, the size of the priority queue indicates the minimum number of clones needed.
Complete Code:
Output:
Minimum clones required: 4