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237. Find three elements in an array that sum to a zero
Objective: Given an array of integers write an algorithm to find 3 elements that sum to a zero. In short a+b+c = 0.
Example
int [] = { 3,-1,-7,-4,-5,9,10}; Elements are -4 9 -5
Approach: Brute Force
Use 3 nested loops and find the 3 elements which sum to 0.
Time Complexity: O(n^3)
Approach: Sorting
- Sort the array.
- Use the other loop to fix the one element at a time, say its ‘a’.
- Now the problem is reduced to "Find a pair of numbers from an array whose sum equals to K"
Time Complexity: O(n^2)
Approach: Use Hashing
- Use the other loop to fix the one element at a time.
- Now required_sum is (with two elements) = -fixed element.
- Create a HashSet, Iterate through the rest of the array.
- For current_element, remain_value = required_sum – current_element.
- Check if remain_value in the HashSet, we have found our triplets else add current_element to the HashSet.
Time Complexity: O(n^2)
Output:
Found 3 elements whose sum is = 0 Elements are -4 9 -5